Tính hợp lý (nếu có thể)
----- Nội dung ảnh -----
Dạng 1: Thực hiện phép tính
Bài 1: Tính hợp lý (nếu có thể)
a) \(\frac{3}{4} - \frac{15}{24} - \frac{1}{3} + \frac{7}{11} + \frac{11}{4} - 3,25\)
b) \(\frac{3}{8} \cdot 27 - \frac{1}{5} - \frac{2}{3} + \frac{8}{3} + 19\)
c) \(\sqrt{0,49} - \sqrt{\frac{16}{25}} + \frac{4}{5} - \sqrt{0,09}\)
d) \(\frac{4}{15} + \frac{7}{11} + \frac{11}{4} - \frac{4}{11}\)
e) \(15 \cdot \left(-\frac{1}{5}\right)^2 - 2 \cdot \left(-\frac{1}{2}\right)\)
f) \(16 \cdot \left(\frac{1}{4}\right) - \frac{5}{4} \cdot \frac{6}{5} + \frac{3}{2} - \frac{8}{5}\)
g) \(\frac{\sqrt{16}}{27} \cdot \frac{81}{8} - \sqrt{0,25} - (-2)^2\)
h) \(0,6 + 0,4 + (-4) \cdot (-5) - 2 \cdot \left(\frac{3}{5}\right)\)
i) \(3,8 + 2,2 + (-6,2) + (-3,8) + 6,2\)
m) \(\sqrt{\frac{4}{25} + \frac{4}{5} - 9 \cdot \left(-\frac{1}{3}\right)^2} + 0,75 \cdot 5: \left(-\frac{5}{2}\right)^2 + 2 \cdot \frac{9}{4} - (-2018)^0 + 0, n\)
\(\left|\frac{5}{3} - \sqrt{25} - 1,12 - \sqrt{\frac{49}{36}} - \frac{2}{7} - \left(-\frac{14}{15}\right)\right|\)
Dạng 1: Thực hiện phép tính
Bài 1: Tính hợp lý (nếu có thể)
a) \(\frac{3}{4} - \frac{15}{24} - \frac{1}{3} + \frac{7}{11} + \frac{11}{4} - 3,25\)
b) \(\frac{3}{8} \cdot 27 - \frac{1}{5} - \frac{2}{3} + \frac{8}{3} + 19\)
c) \(\sqrt{0,49} - \sqrt{\frac{16}{25}} + \frac{4}{5} - \sqrt{0,09}\)
d) \(\frac{4}{15} + \frac{7}{11} + \frac{11}{4} - \frac{4}{11}\)
e) \(15 \cdot \left(-\frac{1}{5}\right)^2 - 2 \cdot \left(-\frac{1}{2}\right)\)
f) \(16 \cdot \left(\frac{1}{4}\right) - \frac{5}{4} \cdot \frac{6}{5} + \frac{3}{2} - \frac{8}{5}\)
g) \(\frac{\sqrt{16}}{27} \cdot \frac{81}{8} - \sqrt{0,25} - (-2)^2\)
h) \(0,6 + 0,4 + (-4) \cdot (-5) - 2 \cdot \left(\frac{3}{5}\right)\)
i) \(3,8 + 2,2 + (-6,2) + (-3,8) + 6,2\)
m) \(\sqrt{\frac{4}{25} + \frac{4}{5} - 9 \cdot \left(-\frac{1}{3}\right)^2} + 0,75 \cdot 5: \left(-\frac{5}{2}\right)^2 + 2 \cdot \frac{9}{4} - (-2018)^0 + 0, n\)
\(\left|\frac{5}{3} - \sqrt{25} - 1,12 - \sqrt{\frac{49}{36}} - \frac{2}{7} - \left(-\frac{14}{15}\right)\right|\)