Giải các phương trình sau

$$\begin{gathered} \frac{1}{4}\left(x+3\right)=3-\frac{1}{2}(x+1)-\frac{1}{3}\left(x+2\right) \\ \frac{3x-11}{11}-\frac{x}{3}=\frac{3x-5}{7}-\frac{5x-3}{9} \\ \frac{9x-0,7}{4}-\frac{5x-1,5}{7}=\frac{7x-11}{6}-\frac{5(0,4-2x)}{6} \\ \frac{2x-{\displaystyle \frac{4-3x}{5}}}{15}=\frac{7x-{\displaystyle \frac{x-3}{2}}}{5}-x+1 \end{gathered}$$

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