Tính giới hạn \(I = \mathop {\lim }\limits_{x \to {2^ - }} \frac{{3{x^2} - 2}}\)

Ta có: \(\left\{ \begin{array}{l}\mathop {\lim }\limits_{x \to {2^ - }} \left( {3{x^2} - 2} \right) = 3.{\left( { - 2} \right)^2} - 2 = 10 >0\\\mathop {\lim }\limits_{x \to {2^ - }} \left( {x - 2} \right) = 2 - 2 = 0\\x \to {2^ - } \Rightarrow x < 2 \Rightarrow x - 2 < 0\end{array} \right. \Rightarrow I = \mathop {\lim }\limits_{x \to {2^ - }} \frac{{3{x^2} - 2}} = - \infty .\)

Đáp án B.