Giải các phương trình sau
Giúp mình với ạ
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Bài 8: Giải các phương trình sau:
1) \( \frac{1}{x+1} + \frac{5}{x^2 - (x+1)(x-2)} = \frac{3x}{(x+1)(x-2)} \)
2) \( \frac{2}{x+1} - \frac{1}{x-2} = \frac{3x - 11}{(x+1)(x-2)} \)
3) \( 2 = \frac{3}{x-20} \)
4) \( x - 2 = \frac{3x - 8}{2x - 6} \)
5) \( \frac{1}{x-1} + \frac{2}{x-2} = 5 \)
6) \( \frac{7}{x+2} + \frac{2}{x+3} = \frac{1}{x^2 + 5x + 6} \)
7) \( \frac{4}{x^2} + \frac{1}{x^2 - 2x - 8} = \frac{3}{x - 4} \)
8) \( \frac{3x + 2}{x + 1} = \frac{1}{x + 3} \)
9) \( \frac{x + 2}{x^2 - 2x - 8} = \frac{x - 4}{x - 4} \)
10) \( \frac{4}{x + 6} + \frac{1}{x - 3} = \frac{2}{x^2 + 3x - 18} \)
11) \( \frac{2}{3x + 1} + \frac{15}{6x^2 - x - 1} = 3 \)
12) \( \frac{4}{x - 2} - \frac{x^2 - 2}{x + 1} = \frac{x^2 - 2}{x^2 - 2} \)
13) \( \frac{2}{x + 6} + \frac{1}{x + 1} = \frac{3x + 8}{x^2 + 7x + 6} \)
14) \( \frac{5}{x - 2} + \frac{2}{x + 4} = \frac{x^2 + 2x - 8}{x - 1} \)
15) \( x - 2 = \frac{3}{x - 11} \)
16) \( \frac{3}{x+2} + \frac{4}{x+4} = \frac{x^2 - 2}{x^2 - 4} \)
17) \( x + 1 - \frac{3}{2x-1} = \frac{2}{x + 2} \)
18) \( x - \frac{2}{x + 4} = \frac{-x^2 + 11}{x + 2} \)
19) \( \frac{x + 1}{x - 1} = \frac{5}{x - 2} \)
20) \( x + 2 - \frac{2}{x - 2} = \frac{-x^2 + 4}{x - 4} \)
21) \( \frac{x}{2x - 6} + \frac{x}{2x + 2} = \frac{-2x}{(3-x)(x+1)} \)
22) \( \frac{1}{x} - \frac{2x - 1}{x^2 + x} = \frac{2}{x^2 + x} \)
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Bài 8: Giải các phương trình sau:
1) \( \frac{1}{x+1} + \frac{5}{x^2 - (x+1)(x-2)} = \frac{3x}{(x+1)(x-2)} \)
2) \( \frac{2}{x+1} - \frac{1}{x-2} = \frac{3x - 11}{(x+1)(x-2)} \)
3) \( 2 = \frac{3}{x-20} \)
4) \( x - 2 = \frac{3x - 8}{2x - 6} \)
5) \( \frac{1}{x-1} + \frac{2}{x-2} = 5 \)
6) \( \frac{7}{x+2} + \frac{2}{x+3} = \frac{1}{x^2 + 5x + 6} \)
7) \( \frac{4}{x^2} + \frac{1}{x^2 - 2x - 8} = \frac{3}{x - 4} \)
8) \( \frac{3x + 2}{x + 1} = \frac{1}{x + 3} \)
9) \( \frac{x + 2}{x^2 - 2x - 8} = \frac{x - 4}{x - 4} \)
10) \( \frac{4}{x + 6} + \frac{1}{x - 3} = \frac{2}{x^2 + 3x - 18} \)
11) \( \frac{2}{3x + 1} + \frac{15}{6x^2 - x - 1} = 3 \)
12) \( \frac{4}{x - 2} - \frac{x^2 - 2}{x + 1} = \frac{x^2 - 2}{x^2 - 2} \)
13) \( \frac{2}{x + 6} + \frac{1}{x + 1} = \frac{3x + 8}{x^2 + 7x + 6} \)
14) \( \frac{5}{x - 2} + \frac{2}{x + 4} = \frac{x^2 + 2x - 8}{x - 1} \)
15) \( x - 2 = \frac{3}{x - 11} \)
16) \( \frac{3}{x+2} + \frac{4}{x+4} = \frac{x^2 - 2}{x^2 - 4} \)
17) \( x + 1 - \frac{3}{2x-1} = \frac{2}{x + 2} \)
18) \( x - \frac{2}{x + 4} = \frac{-x^2 + 11}{x + 2} \)
19) \( \frac{x + 1}{x - 1} = \frac{5}{x - 2} \)
20) \( x + 2 - \frac{2}{x - 2} = \frac{-x^2 + 4}{x - 4} \)
21) \( \frac{x}{2x - 6} + \frac{x}{2x + 2} = \frac{-2x}{(3-x)(x+1)} \)
22) \( \frac{1}{x} - \frac{2x - 1}{x^2 + x} = \frac{2}{x^2 + x} \)