22^x + 4*2^x = 72

Tìm x:
1) 3*5^2x + 1 - 3*25^x = 300
2) 16^x/4^x = 16
3) (2/x + 1)^3 = - 64
4) (3*x - 2)^2 = 81
5) 1/2*2^x + 4*2^x = 72

Tìm x: 1) 3*5^2x + 1 - 3*25^x = 300; 2) 16^x/4^x = 16; 3) (2/x + 1)^3 = - 64; 4) (3*x - 2)^2 = 81; 5) 1/2*2^x + 4*2^x = 72