Tính I = 3 $\sqrt{\frac{4}{3}} - \frac{8 + 2\sqrt{2}}{3 - \sqrt{2}} + \frac{4 - 6\sqrt{2}}{\sqrt{2}} + \frac{\sqrt{3}}{\sqrt{3} - 2}$

----- Nội dung ảnh -----
I = 3

$\sqrt{\frac{4}{3}} - \frac{8 + 2\sqrt{2}}{3 - \sqrt{2}} + \frac{4 - 6\sqrt{2}}{\sqrt{2}} + \frac{\sqrt{3}}{\sqrt{3} - 2}$

Tính I = 3√43−8+2√23−√2+4−6√2√2+√3√3−2\sqrt{\frac{4}{3}} - \frac{8 + 2\sqrt{2}}{3 - \sqrt{2}} + \frac{4 - 6\sqrt{2}}{\sqrt{2}} + \frac{\sqrt{3}}{\sqrt{3} - 2}