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13) \(\frac{x - 1}{x + 1} - \frac{x^2 + x - 2}{x + 1} = \frac{x + 1}{x - 1} - x - 2\)
14) \(\frac{x + 1}{x - 1} - \frac{x - 1}{x + 1} = \frac{4}{x^2 - 1}\)
15) \(\frac{8x^2}{3(1 - 4x^2)} = \frac{2x - 1 + 8x}{6x - 3} = \frac{4 + 8x}{4 + 8x}\)
16) \(\frac{1}{x + 1} - \frac{5}{x - 2} = \frac{15}{(x + 1)(2 - x)}\)
17) \(\frac{6}{x - 1} - \frac{4}{x - 3} = 8\)
18) \(\frac{x + 2}{x - 2} - \frac{1}{x} = \frac{2}{x(x - 2)}\)
19) \(\frac{1}{x - 1} + \frac{2x^2 - 5}{x^3 - 1} = \frac{4}{x^2 + x + 1}\)
20) \(\frac{1}{x - 1} - \frac{3x^2}{x^3 - 1} = \frac{2x}{x^2 + x + 1}\)
----- Nội dung ảnh -----
13) \(\frac{x - 1}{x + 1} - \frac{x^2 + x - 2}{x + 1} = \frac{x + 1}{x - 1} - x - 2\)
14) \(\frac{x + 1}{x - 1} - \frac{x - 1}{x + 1} = \frac{4}{x^2 - 1}\)
15) \(\frac{8x^2}{3(1 - 4x^2)} = \frac{2x - 1 + 8x}{6x - 3} = \frac{4 + 8x}{4 + 8x}\)
16) \(\frac{1}{x + 1} - \frac{5}{x - 2} = \frac{15}{(x + 1)(2 - x)}\)
17) \(\frac{6}{x - 1} - \frac{4}{x - 3} = 8\)
18) \(\frac{x + 2}{x - 2} - \frac{1}{x} = \frac{2}{x(x - 2)}\)
19) \(\frac{1}{x - 1} + \frac{2x^2 - 5}{x^3 - 1} = \frac{4}{x^2 + x + 1}\)
20) \(\frac{1}{x - 1} - \frac{3x^2}{x^3 - 1} = \frac{2x}{x^2 + x + 1}\)