Tìm x, y biết
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o/ \(\frac{1}{xy - x^2} \frac{1}{y^2 - xy}\)
t/ \(\frac{x+1}{x^4 - 4} \frac{x^2 - 16}{x^2}\)
v/ \(\sqrt{\frac{-3x}{2x} + \frac{3x - 2}{2x - 1} + \frac{3x - 2}{2x - 4x^2}}\)
w/ \(\frac{5x - 2}{15} + \frac{2x + 2}{15}\)
y/ \(\frac{x^2}{x + y} + \frac{y^2}{y + z} - \frac{y^2}{x + y} - \frac{z^2}{y + z}\) ;
J/ \(A = \frac{20x^2 + 120x + 180}{(3x + 5)^2 - 4x^2} + \frac{5x^2 - 125}{(2x + 3)^2 - x^2}\) .
o/ \(\frac{1}{xy - x^2} \frac{1}{y^2 - xy}\)
t/ \(\frac{x+1}{x^4 - 4} \frac{x^2 - 16}{x^2}\)
v/ \(\sqrt{\frac{-3x}{2x} + \frac{3x - 2}{2x - 1} + \frac{3x - 2}{2x - 4x^2}}\)
w/ \(\frac{5x - 2}{15} + \frac{2x + 2}{15}\)
y/ \(\frac{x^2}{x + y} + \frac{y^2}{y + z} - \frac{y^2}{x + y} - \frac{z^2}{y + z}\) ;
J/ \(A = \frac{20x^2 + 120x + 180}{(3x + 5)^2 - 4x^2} + \frac{5x^2 - 125}{(2x + 3)^2 - x^2}\) .