Giải các phương trình sau: \( \frac{1}{x-2} + \frac{1}{x^2} = 3 \)
giúp t vs mn ơi
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Bài 9. Giải các phương trình sau:
1. \( \frac{1}{x-2} + \frac{1}{x^2} = 3 \)
\( \frac{3}{x+1} = \frac{3}{x-2} \)
\( \frac{3}{x^3} = -9 \)
2. \( \frac{x}{x+1} = \frac{4}{x^2} \)
3. \( \frac{x}{x+1} = \frac{4}{x^2-5} \)
4. \( \frac{x}{x^4} = \frac{7}{x^2-2} \)
5. \( \frac{x^2 - 5}{x^2 - 17x + 56} \)
6. \( \frac{x^2 - 1}{x^2 - 12} \)
7. \( \frac{x^2 + 2}{x^4 - 1} = \)
8. \( \frac{x^3 - 2x}{9x - 5} = \frac{x^2 - 25}{x^2 - 25} \)
9. \( 2x - 3x = 5 + x^5 \)
10. \( \frac{x^2 + 7}{x^4 + x + 4} \)
11. \( \frac{x^2 + 2}{x + 4} = \frac{7}{x - 4} \)
12. \( \frac{x^2 - 1}{2x^2 - 1} \)
13. \( \frac{4x^2}{2x + 1} = -16 \)
14. \( \frac{x^3 + 3x}{x^4 - 1} \)
15. \( \frac{x^2 - 2}{x - 4} \)
16. \( \frac{1}{x+1} = \frac{3}{x^2 + 1} \)
17. \( \frac{x^3 + 3}{x^2 + 1} = \frac{x^2 - 3x + 2}{x^2 - 4} \)
18. \( x - 3 = 2(x + 12) \)
19. \( \frac{x^3 - 1}{2x^2 + 1} = \frac{2x^2 - 3x + 2}{x^2 - 1} \)
20. \( \frac{2(x+12)}{x^2 - 1} = \)
----- Nội dung ảnh -----
Bài 9. Giải các phương trình sau:
1. \( \frac{1}{x-2} + \frac{1}{x^2} = 3 \)
\( \frac{3}{x+1} = \frac{3}{x-2} \)
\( \frac{3}{x^3} = -9 \)
2. \( \frac{x}{x+1} = \frac{4}{x^2} \)
3. \( \frac{x}{x+1} = \frac{4}{x^2-5} \)
4. \( \frac{x}{x^4} = \frac{7}{x^2-2} \)
5. \( \frac{x^2 - 5}{x^2 - 17x + 56} \)
6. \( \frac{x^2 - 1}{x^2 - 12} \)
7. \( \frac{x^2 + 2}{x^4 - 1} = \)
8. \( \frac{x^3 - 2x}{9x - 5} = \frac{x^2 - 25}{x^2 - 25} \)
9. \( 2x - 3x = 5 + x^5 \)
10. \( \frac{x^2 + 7}{x^4 + x + 4} \)
11. \( \frac{x^2 + 2}{x + 4} = \frac{7}{x - 4} \)
12. \( \frac{x^2 - 1}{2x^2 - 1} \)
13. \( \frac{4x^2}{2x + 1} = -16 \)
14. \( \frac{x^3 + 3x}{x^4 - 1} \)
15. \( \frac{x^2 - 2}{x - 4} \)
16. \( \frac{1}{x+1} = \frac{3}{x^2 + 1} \)
17. \( \frac{x^3 + 3}{x^2 + 1} = \frac{x^2 - 3x + 2}{x^2 - 4} \)
18. \( x - 3 = 2(x + 12) \)
19. \( \frac{x^3 - 1}{2x^2 + 1} = \frac{2x^2 - 3x + 2}{x^2 - 1} \)
20. \( \frac{2(x+12)}{x^2 - 1} = \)