Giải các phương trình sau

----- Nội dung ảnh -----
```
g) 40 - \frac{9x^2}{x^2 + 3x + 2} = 1
h) \frac{9}{10 + (x + 3)^2} = x^2
i) \frac{40 - x + 9}{10 - x + 9} = x + 7
a) (2x + 7)^2 = 9(x + 2)^2
b) (3x - 2)^{2} = (x - 1)^{2}
c) 2x(8x + 4)(x - 1)^{2}(4x - 1) = 9
d) (4x - 5)(2x - 1)^{2}(x - 1)(6x + 7)^{2} = 6
e) (4x - 5)(2x - 1)^{2} = (x + 1)(3x - 5)
f) (x^2 - 4x + 2)(x - 2)^{2} = 9
1) \frac{1}{x^2 + 7x + 12}
2) \frac{1}{x^2 + 9x + 20} = 3
11) \frac{1}{x + 8}
12) \frac{1}{x + 7}
```