BÀI TẬP VỀ SỐ HỮU TỈ
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BÀI TẬP VỀ SỐ HỮU TỈ
**Bài 1:** Thực hiện các phép tính sau:
A= \(\frac{1}{2} - \frac{3}{4} + \frac{5}{7} = \frac{7}{12}\)
B= \(-3 - \frac{2}{5} + \frac{10}{9} - \frac{25}{3} = -\frac{5}{6}\)
C= \(\frac{12}{35} - \frac{18}{14} - \frac{6}{7} - 2 = -1\)
D= \(\left[-\frac{54}{64} - \left(\frac{1}{9} \cdot \frac{8}{27} - \frac{1}{3}\right) \cdot -\frac{81}{128}\right]\)
E= \(\frac{193}{-17} \cdot \left(\frac{2}{193} - \frac{3}{386}\right) + \left[\frac{11}{34} \cdot \left(\frac{7}{1931} + \frac{11}{3862}\right)\right] \cdot \left(\frac{1931}{25} + \frac{9}{2}\right)\)
F= \(\left(\frac{53}{4} - \frac{2}{5} \cdot \frac{65}{27}\right) \cdot \left(230 + \frac{1}{25}\right) + \frac{46 \cdot \frac{3}{4}}{\cdots}\)
G= \(\frac{-5 + \frac{7}{9} + \frac{9}{11} - \frac{11}{13}}{\frac{3}{4}}\)
**Bài 2:** Tìm số hữu tỉ x biết rằng:
a) \(-\frac{3}{2} - 2x + \frac{3}{4} = -2\)
b) \(\left(-\frac{2}{3}x - \frac{3}{5}\right)\left(\frac{3}{-2} - 10\right) = \frac{2}{5}\)
c) \(\frac{x}{2} - \frac{3x}{5} - \frac{13}{5} = -\left(\frac{7}{5} + 7 \cdot x\right)\)
d) \(2x - \frac{3}{3} + \frac{3}{6} = -5 - 3x - \frac{1}{3}\)
e) \(\frac{2}{3x} - \frac{3}{12} = \frac{4}{5}\left(\frac{7}{x} - 2\right)\)
f*) \(\frac{1}{x-1} + \frac{-2}{3}\left(\frac{3}{6} + \frac{4}{5}\right) = \frac{5}{2-2x}\)
g*) \(\frac{x - 2}{2} - \frac{3}{5} + \frac{9}{6}x = \frac{3}{2}\)
BÀI TẬP VỀ SỐ HỮU TỈ
**Bài 1:** Thực hiện các phép tính sau:
A= \(\frac{1}{2} - \frac{3}{4} + \frac{5}{7} = \frac{7}{12}\)
B= \(-3 - \frac{2}{5} + \frac{10}{9} - \frac{25}{3} = -\frac{5}{6}\)
C= \(\frac{12}{35} - \frac{18}{14} - \frac{6}{7} - 2 = -1\)
D= \(\left[-\frac{54}{64} - \left(\frac{1}{9} \cdot \frac{8}{27} - \frac{1}{3}\right) \cdot -\frac{81}{128}\right]\)
E= \(\frac{193}{-17} \cdot \left(\frac{2}{193} - \frac{3}{386}\right) + \left[\frac{11}{34} \cdot \left(\frac{7}{1931} + \frac{11}{3862}\right)\right] \cdot \left(\frac{1931}{25} + \frac{9}{2}\right)\)
F= \(\left(\frac{53}{4} - \frac{2}{5} \cdot \frac{65}{27}\right) \cdot \left(230 + \frac{1}{25}\right) + \frac{46 \cdot \frac{3}{4}}{\cdots}\)
G= \(\frac{-5 + \frac{7}{9} + \frac{9}{11} - \frac{11}{13}}{\frac{3}{4}}\)
**Bài 2:** Tìm số hữu tỉ x biết rằng:
a) \(-\frac{3}{2} - 2x + \frac{3}{4} = -2\)
b) \(\left(-\frac{2}{3}x - \frac{3}{5}\right)\left(\frac{3}{-2} - 10\right) = \frac{2}{5}\)
c) \(\frac{x}{2} - \frac{3x}{5} - \frac{13}{5} = -\left(\frac{7}{5} + 7 \cdot x\right)\)
d) \(2x - \frac{3}{3} + \frac{3}{6} = -5 - 3x - \frac{1}{3}\)
e) \(\frac{2}{3x} - \frac{3}{12} = \frac{4}{5}\left(\frac{7}{x} - 2\right)\)
f*) \(\frac{1}{x-1} + \frac{-2}{3}\left(\frac{3}{6} + \frac{4}{5}\right) = \frac{5}{2-2x}\)
g*) \(\frac{x - 2}{2} - \frac{3}{5} + \frac{9}{6}x = \frac{3}{2}\)