C) \(\frac{3x-1}{x-1} - \frac{2x+5}{x+3} + \frac{4}{x^2+2x-3} = 1\) d) \(\frac{1}{x-1} - \frac{x}{x^2+x+1} = \frac{4x}{x^3-1}\)
GIẢI PT (KO LÀM TẮT MỚI CHẤM)
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c) \(\frac{3x-1}{x-1} - \frac{2x+5}{x+3} + \frac{4}{x^2+2x-3} = 1\)
d) \(\frac{1}{x-1} - \frac{x}{x^2+x+1} = \frac{4x}{x^3-1}\)