Tìm x biết :
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1) \( \frac{1}{3}x - \frac{2}{5}(x+1) = 0 \)
2) \( x + \frac{3}{4} - \frac{5}{5} = - x \)
3) \( 5x \left(2x - \frac{1}{2}\right) + 2 \left(2x - \frac{1}{2}\right) = 0 \)
4) \( 2x(x+1) - x(8+2x) = -3 \)
**Bài 6. Tìm x biết**
a) \( \left(2x + 3\right)^{2} = \frac{9}{25} \)
b) \( \frac{x^{2} + 6}{105} = 0.1 \)
c) \( \left(-\frac{3}{5}\right)^{3} = 3 \cdot \frac{1}{25}^{2} \)
d) \( \left(\frac{1}{3}\right)^{x + 4} = \left(-\frac{1}{27}\right)^{10} \)
e) \( 7.3^{-1} - 3x^{2} = -540 \)
f) \( \left(\frac{1}{2}\right)^{x + 1} + \left(\frac{1}{2}\right)^{x + 3} = \frac{5}{32} \)
g) \( (x^{4} - 1)(\sqrt{x - 3}) = 0 \, (x \geq 0) \)
**Bài 7. Tìm x biết**
a) \( 2 - \sqrt{x} = -7 \, (x \geq 0) \)
b) \( 25 - \sqrt{x} - 5 = 9 \, (x \geq 5) \)
c) \( \frac{2}{9} - \sqrt{(x + 1)}^{2} = -\frac{23}{9} \)
d) \( 3 \cdot \frac{1}{x + 1} - \frac{1}{4} = 5 \, (x \geq -1) \)
e) \( \frac{1}{5} \sqrt{3x + 2} = 1 \, | \, x \leq -\frac{2}{3} \)
**Bài 8. Tìm x biết**
a) \( |x + 3| - \frac{5}{6} = 1 \, (3) \)
b) \( \frac{1}{2} |2x + 1| = -\sqrt{0.25} \)
c) \( \frac{1}{4} |x| = \left(-\frac{1}{4}\right)^{2} - \left(-\frac{1}{4}\right)^{3} \)
d) \( |2x - 1| - 0.5 + |1| = 0 \)
1) \( \frac{1}{3}x - \frac{2}{5}(x+1) = 0 \)
2) \( x + \frac{3}{4} - \frac{5}{5} = - x \)
3) \( 5x \left(2x - \frac{1}{2}\right) + 2 \left(2x - \frac{1}{2}\right) = 0 \)
4) \( 2x(x+1) - x(8+2x) = -3 \)
**Bài 6. Tìm x biết**
a) \( \left(2x + 3\right)^{2} = \frac{9}{25} \)
b) \( \frac{x^{2} + 6}{105} = 0.1 \)
c) \( \left(-\frac{3}{5}\right)^{3} = 3 \cdot \frac{1}{25}^{2} \)
d) \( \left(\frac{1}{3}\right)^{x + 4} = \left(-\frac{1}{27}\right)^{10} \)
e) \( 7.3^{-1} - 3x^{2} = -540 \)
f) \( \left(\frac{1}{2}\right)^{x + 1} + \left(\frac{1}{2}\right)^{x + 3} = \frac{5}{32} \)
g) \( (x^{4} - 1)(\sqrt{x - 3}) = 0 \, (x \geq 0) \)
**Bài 7. Tìm x biết**
a) \( 2 - \sqrt{x} = -7 \, (x \geq 0) \)
b) \( 25 - \sqrt{x} - 5 = 9 \, (x \geq 5) \)
c) \( \frac{2}{9} - \sqrt{(x + 1)}^{2} = -\frac{23}{9} \)
d) \( 3 \cdot \frac{1}{x + 1} - \frac{1}{4} = 5 \, (x \geq -1) \)
e) \( \frac{1}{5} \sqrt{3x + 2} = 1 \, | \, x \leq -\frac{2}{3} \)
**Bài 8. Tìm x biết**
a) \( |x + 3| - \frac{5}{6} = 1 \, (3) \)
b) \( \frac{1}{2} |2x + 1| = -\sqrt{0.25} \)
c) \( \frac{1}{4} |x| = \left(-\frac{1}{4}\right)^{2} - \left(-\frac{1}{4}\right)^{3} \)
d) \( |2x - 1| - 0.5 + |1| = 0 \)