4) Tìm x: a) \(\frac{x-241}{17} + \frac{x-320}{19} + \frac{x-195}{21} + \frac{x-166}{23} = 10\) b) \((3x-3)(2x+1)^2(3x+8) = -16\)

4) Tìm x: a) \(\frac{x-241}{17} + \frac{x-320}{19} + \frac{x-195}{21} + \frac{x-166}{23} = 10\)
b) \((3x-3)(2x+1)^2(3x+8) = -16\)