1) \(\frac{1 - 3x}{6} + \frac{x - 1}{2} = x + 2\) h) \(\frac{3(2x + 1)}{4} - \frac{5 - 3x + 2}{10} = \frac{2(3x - 1)}{5}\)
----- Nội dung ảnh -----
1) \(\frac{1 - 3x}{6} + \frac{x - 1}{2} = x + 2\)
h) \(\frac{3(2x + 1)}{4} - \frac{5 - 3x + 2}{10} = \frac{2(3x - 1)}{5}\)