Tìm x

$$\begin{gathered} o)\frac{1}{9}{(x-3)}^{2 }-\frac{1}{5}\left(x+5\right)=0 \\ p) {\left(\frac{3x}{5}-\frac{1}{3}\right)}^2={\left(\frac{x}{5}+\frac{2}{3}\right)}^2 \\ q) {\left(\frac{2x}{3}+1\right)}^2={\left(\frac{3x}{2}-1\right)}^2 \\ r) {\left(x+1+\frac{1}{x}\right)}^2={\left(x-1-\frac{1}{x}\right)}^2 \end{gathered}$$