Giải phương trình: 4/(25x^2+20x-3)=3/(5x-1)-2(5x-3)

$$\begin{gathered} \frac{4}{25x^2+20x-3}=\frac{3}{5x-1}-\frac{2}{5x-3} \\ \frac{1}{x^2-3x+2}+\frac{1}{x^2-5x+6}-\frac{2}{x^2-4x+3} \\ \frac{x-1}{2x^2-4x}-\frac{7}{8x}=\frac{5-x}{4x^2-8x}-\frac{1}{8x-16} \\ \frac{1}{x^2+9x+20}+\frac{1}{x^2+11x+30}+\frac{1}{x^2+13x+42}=\frac{1}{18} \end{gathered}$$