Cho tam giác ABC có: góc A = 90 độ

$\mathrm{\Delta ABC}:\hat{\mathrm{A}}$$={90}^0,$$\mathrm{AB}=3\mathrm{cm},BC=5\mathrm{cm}. \mathrm{So} \mathrm{sánh}$$\widehat{\mathrm{B} }và \hat{\mathrm{C}}$