Giải phương trình

$$\begin{gathered} a,\frac{5x+3}{12}=\frac{1+2x}{9} \\ b,\frac{7x-1}{6}=\frac{16-x}{5} \\ c,\frac{x-3}{5}=6-\frac{1-2x}{3} \\ d,\frac{3-2x}{6}-5=\frac{3-2(x=7)}{4} \\ e,\frac{3x-7}{2}=\frac{x+1}{3}=-16 \\ g,x-\frac{x+1}{3}=\frac{2x+1}{5} \\ h,\frac{2x-1}{3}-\frac{5x+2}{7}=x+14 \end{gathered}$$