Tìm x √(2x + 1)^2 = 5

$$\begin{gathered} a/ \sqrt{(2x + 1)^2} = 5 \\ b/ \sqrt{9x^2 - 6x +1} - 2=0 \\ c/ \sqrt{x^2 + 4x + 4} = 2x - 1 \\ d/ 2x - \sqrt{x^2 + 2x +1} = 1 \\ e/\sqrt{9 - 6x + x^2} = x \end{gathered}$$