Tìm x. x^2-4x+4 = x-4

Tìm x
$$\begin{gathered} \sqrt{{\mathrm{x}}^2-4\mathrm{x}+4}=x-4 \\ \sqrt{{\mathrm{x}}^2-2\mathrm{x}+1}=3 \\ \sqrt{4{\mathrm{x}}^2-10\mathrm{x}+25}+2x=5 \end{gathered}$$