Tìm x: a) (x + 3)(x2 – 3x + 9) – x(x – 2)2 = 27; b) (2x + 3)(x – 1) + (2x – 3)(1 – x) = 0

Bài 3: Tìm x:
a) (x + 3)(x2 – 3x + 9) – x(x – 2)2 = 27
b) (2x + 3)(x – 1) + (2x – 3)(1 – x) = 0
c) 3x3 – 12x = 0
d) 2x (3x – 5) = 10 – 6x
e) (x – 1)(x – 5) + 3 = 0
f) 2(x – 2) = x2 – 4x + 4
e) 2x2 – 5x – 3 = 0
g) x2 – 6x + 9 = 25
h) (5x – 4)2 = 49x2
k) x3 + x2 – x – 1 = 0