Rút gọn P = (2x/(x+3)+x/(x-3)+(3x^2+3)/(9-x^2 )) : ((2x-2)/(x-3)-1)

P=(2x/(x+3)+x/(x-3)+(3x^2+3)/(9-x^2 )):((2x-2)/(x-3)-1)
mik dang can gap a mik hua se danh gia 5sao neu tra loi dung ak
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