Tìm x, ta có
----- Nội dung dịch tự động từ ảnh -----
19) \(\frac{x+1}{2x-2} = \frac{2}{2x-1}\)
20) \(\frac{x+1}{x+2} + \frac{5}{x^2-1} = 1\)
21) \(\frac{x}{2x-6} + \frac{2}{2x+2} = \frac{(3-x)(x+1)}{(x-1)(x+1)}\)
22) \(\frac{1}{x^2-1} + \frac{2}{x+2} = \frac{3}{2x+2}\)
23) \(\frac{9x^2}{x^3-8} + \frac{6}{2x+4} = -2\)
24) \(\frac{2x}{x^2+x+1} - \frac{1}{1-x^3} = 1\)
25) \(\frac{1}{x-1} + \frac{1}{x^2+x+1} - \frac{x^2+2}{x^3-1} = 0\)
26) \(\frac{1}{x+2} - \frac{2}{x^3-9} = 2\)
27) \(\frac{1}{x-1} + \frac{1}{x^2+x+1} - \frac{x^2+2}{x^3-1} = 0\)
vô nghiệm
19) \(\frac{x+1}{2x-2} = \frac{2}{2x-1}\)
20) \(\frac{x+1}{x+2} + \frac{5}{x^2-1} = 1\)
21) \(\frac{x}{2x-6} + \frac{2}{2x+2} = \frac{(3-x)(x+1)}{(x-1)(x+1)}\)
22) \(\frac{1}{x^2-1} + \frac{2}{x+2} = \frac{3}{2x+2}\)
23) \(\frac{9x^2}{x^3-8} + \frac{6}{2x+4} = -2\)
24) \(\frac{2x}{x^2+x+1} - \frac{1}{1-x^3} = 1\)
25) \(\frac{1}{x-1} + \frac{1}{x^2+x+1} - \frac{x^2+2}{x^3-1} = 0\)
26) \(\frac{1}{x+2} - \frac{2}{x^3-9} = 2\)
27) \(\frac{1}{x-1} + \frac{1}{x^2+x+1} - \frac{x^2+2}{x^3-1} = 0\)
vô nghiệm