Tính: d) \(\sqrt{16a} - 2\sqrt{25a} + \frac{3}{2}\sqrt{64a}\) \((a > 0)\), e) \(\left(\sqrt{\frac{4a}{9}} - 9a + \frac{3}{2}\sqrt{16a}\right) \cdot \sqrt{a}\) \((a > 0)\)

giải phép tính căn bậc hai số thực :
----- Nội dung ảnh -----
d) \(\sqrt{16a} - 2\sqrt{25a} + \frac{3}{2}\sqrt{64a}\) \((a > 0)\)

e) \(\left(\sqrt{\frac{4a}{9}} - 9a + \frac{3}{2}\sqrt{16a}\right) \cdot \sqrt{a}\) \((a > 0)\)

f) \(\sqrt{\frac{2a}{4}} \cdot \frac{4}{5}\sqrt{8a} - \sqrt{\frac{2a}{9}}\) \((a > 0)\)