Tìm x, biết:
giúppp làm một bài cũm đc gấpppp
----- Nội dung ảnh -----
Bài toán 5: Tìm x, bi t:
a) \( x - \frac{1}{5} = \frac{3}{2} + \frac{1}{6} \)
b) \( \frac{16}{5} - x = \frac{4}{5} - \frac{3}{10} \)
c) \( \frac{1}{20} \left( - (x - \frac{8}{5}) \right) = \frac{1}{10} \)
d) \( x + \frac{1}{3} = \frac{2}{5} + \frac{3}{2} \)
e) \( \frac{1}{2} \left( - (x + \frac{1}{3}) \right) = \frac{5}{6} \)
f) \( \left( \frac{3}{8} - \frac{1}{5} \right) + \left( \frac{5}{8} - x \right) = \frac{1}{5} \)
Bài toán 6: Tìm x, bi t:
a) \( |x + 1| - \frac{2}{3} = - \frac{3}{5} \)
b) \( |x + \frac{3}{4}| + \frac{1}{3} = \frac{5}{6} \)
c) \( \frac{9}{2} \left[ \frac{2}{3} \left( - (x - \frac{7}{4}) \right) \right] = - \frac{5}{4} \)
d) \( \frac{4}{3} \left( x - \frac{1}{5} \right) = | - \frac{3}{10} + \frac{1}{2} - \frac{1}{6} | \)
----- Nội dung ảnh -----
Bài toán 5: Tìm x, bi t:
a) \( x - \frac{1}{5} = \frac{3}{2} + \frac{1}{6} \)
b) \( \frac{16}{5} - x = \frac{4}{5} - \frac{3}{10} \)
c) \( \frac{1}{20} \left( - (x - \frac{8}{5}) \right) = \frac{1}{10} \)
d) \( x + \frac{1}{3} = \frac{2}{5} + \frac{3}{2} \)
e) \( \frac{1}{2} \left( - (x + \frac{1}{3}) \right) = \frac{5}{6} \)
f) \( \left( \frac{3}{8} - \frac{1}{5} \right) + \left( \frac{5}{8} - x \right) = \frac{1}{5} \)
Bài toán 6: Tìm x, bi t:
a) \( |x + 1| - \frac{2}{3} = - \frac{3}{5} \)
b) \( |x + \frac{3}{4}| + \frac{1}{3} = \frac{5}{6} \)
c) \( \frac{9}{2} \left[ \frac{2}{3} \left( - (x - \frac{7}{4}) \right) \right] = - \frac{5}{4} \)
d) \( \frac{4}{3} \left( x - \frac{1}{5} \right) = | - \frac{3}{10} + \frac{1}{2} - \frac{1}{6} | \)