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 Giúp mình Câu 3 ,6 ,7,8,9,10
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BTVN
1. $\sqrt{x+4} - \sqrt{1-x} - \sqrt{2-x}$
2. $\sqrt{3x+4} - 2x + 7 = \sqrt{2x+3}$
3. $2\sqrt{2}$
4. $\sqrt{3x+1} - 3 = \sqrt{2x+3}$
5. $x^2 - 2x + 6 - 2x^{2} + 3 = 0$
6. $x - 2 + x + 6 - 2x + 3 = 0$
7. $C(x+5) C(2-x) = 3\sqrt{2x^{2}+3}$
8. $\sqrt{2x+4} + \sqrt{2-x} = x$
9. $\frac{\sqrt{x}-1}{\sqrt{5} - \sqrt{2}} + \frac{4}{\sqrt{5} + \sqrt{2}} = 2 \left( x + \frac{1}{4} \right)$
10. $5\sqrt{x} \tau + \frac{5}{2\sqrt{2}} = -2 \left( 2 + \frac{1}{4}\sqrt{2} + 2 \right)$

Bài 1
$\sqrt{x+4} = \sqrt{1-2x} + \sqrt{1-x}$ $(x>4)$ $Dk: x\leq1$ $x\leq\frac{1}{2}$