Rút gọn
Giúp mình Câu 3 ,6 ,7,8,9,10
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BTVN
1. \( \sqrt{x+4} - \sqrt{1-x} - \sqrt{2-x} \)
2. \( \sqrt{3x+4} - 2x + 7 = \sqrt{2x+3} \)
3. \( 2\sqrt{2} \)
4. \( \sqrt{3x+1} - 3 = \sqrt{2x+3} \)
5. \( x^2 - 2x + 6 - 2x^{2} + 3 = 0 \)
6. \( x - 2 + x + 6 - 2x + 3 = 0 \)
7. \( C(x+5) C(2-x) = 3\sqrt{2x^{2}+3} \)
8. \( \sqrt{2x+4} + \sqrt{2-x} = x \)
9. \( \frac{\sqrt{x}-1}{\sqrt{5} - \sqrt{2}} + \frac{4}{\sqrt{5} + \sqrt{2}} = 2 \left( x + \frac{1}{4} \right) \)
10. \( 5\sqrt{x} \tau + \frac{5}{2\sqrt{2}} = -2 \left( 2 + \frac{1}{4}\sqrt{2} + 2 \right) \)
Bài 1
\( \sqrt{x+4} = \sqrt{1-2x} + \sqrt{1-x} \) \( (x>4) \) \( Dk: x\leq1 \) \( x\leq\frac{1}{2} \)
----- Nội dung ảnh -----
BTVN
1. \( \sqrt{x+4} - \sqrt{1-x} - \sqrt{2-x} \)
2. \( \sqrt{3x+4} - 2x + 7 = \sqrt{2x+3} \)
3. \( 2\sqrt{2} \)
4. \( \sqrt{3x+1} - 3 = \sqrt{2x+3} \)
5. \( x^2 - 2x + 6 - 2x^{2} + 3 = 0 \)
6. \( x - 2 + x + 6 - 2x + 3 = 0 \)
7. \( C(x+5) C(2-x) = 3\sqrt{2x^{2}+3} \)
8. \( \sqrt{2x+4} + \sqrt{2-x} = x \)
9. \( \frac{\sqrt{x}-1}{\sqrt{5} - \sqrt{2}} + \frac{4}{\sqrt{5} + \sqrt{2}} = 2 \left( x + \frac{1}{4} \right) \)
10. \( 5\sqrt{x} \tau + \frac{5}{2\sqrt{2}} = -2 \left( 2 + \frac{1}{4}\sqrt{2} + 2 \right) \)
Bài 1
\( \sqrt{x+4} = \sqrt{1-2x} + \sqrt{1-x} \) \( (x>4) \) \( Dk: x\leq1 \) \( x\leq\frac{1}{2} \)