Tìm x, x + \(\frac{1}{4}\) = \(\frac{6}{5} \cdot \frac{15}{8}\)

Giúp mình với ạ, mik vote 5 sao và 5đ ạ.mình cảm ơn
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m)x + \(\frac{1}{4}\) = \(\frac{6}{5} \cdot \frac{15}{8}\)

n) \(\frac{x}{-16}\) = \(\frac{-1}{3} \cdot \frac{6}{4}\)

g) \(\frac{7}{12} \left( \frac{x - 5}{12} \right) = \frac{-3}{4}\)

i) \(\frac{1}{2}x + \frac{1}{8}x = \frac{3}{4}\)

a) \(\frac{x + 5}{4} = \frac{x - 3}{5}\)

c) \(x: \frac{3}{4} + \frac{1}{4} = \frac{-2}{3}\)

b) \(\frac{-4}{x - 2} = \frac{x - 2}{-4}\)

d) \(\frac{-7}{x - 4} = \frac{4 - x}{7}\)

g) \(\frac{2x - 3}{3} + \frac{-3}{2} = \frac{5 - 3x}{6} - \frac{1}{3}\)

e) \(\left( \frac{-3}{5} \cdot \frac{x - 1}{2} \right) \cdot \frac{3}{4} \cdot (-1) = \frac{1}{3}\)