Tìm x, biết:
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Bài 2: Tìm x, biết:
a) \(\frac{2}{3} + x = -\frac{1}{12}\)
b) \(\frac{1}{5} + \frac{4}{5} \cdot x = \frac{3}{4}\)
c) \(\frac{8}{5} - \frac{3}{5} \cdot x = 0,4\)
d) \(\frac{5}{11} x + 4 = 6 \frac{1}{11}\)
e) \((2x + 1)^2 = \frac{36}{25}\)
f) \(\left( \frac{1}{3} - \frac{3}{2} x \right)^2 = \frac{9}{4}\)
g) \((3x - 1)^3 = -\frac{1}{27}\)
h) \(\left| \frac{1}{2} x - \frac{3}{4} \right| - 2 = -\frac{3}{2}\)
i) \(3 \left( \left| x - \frac{4}{5} \right| + 0.2 \right) = 0,5\)
j) \((2x + 1) \left( x - \frac{1}{7} \right) = 0\)
k) \(\left( \frac{15}{4} - 5x \right) \cdot (9x^2 - 4) = 0\)
l) \(10\sqrt{x} - 5 = 25 \text{ với } x \ge 0\)
m) \(\sqrt{x - 2} + \frac{1}{3} = 1 \text{ với } x \ge 2\)
n) \(7 \cdot 2^x + 72 \cdot 2^{x + 3} = 344\)
o) \(\frac{2}{x + 3} - \frac{1}{3} = -\frac{5}{12}\)
p) \(x - 4 = \frac{2}{3x}\)
q) \(3 = \frac{12}{x}\)
r) \(\frac{2^{x - 1}}{-3} = \frac{27}{1 - 2x} \text{ với } x \neq \frac{1}{2}\)
Bài 2: Tìm x, biết:
a) \(\frac{2}{3} + x = -\frac{1}{12}\)
b) \(\frac{1}{5} + \frac{4}{5} \cdot x = \frac{3}{4}\)
c) \(\frac{8}{5} - \frac{3}{5} \cdot x = 0,4\)
d) \(\frac{5}{11} x + 4 = 6 \frac{1}{11}\)
e) \((2x + 1)^2 = \frac{36}{25}\)
f) \(\left( \frac{1}{3} - \frac{3}{2} x \right)^2 = \frac{9}{4}\)
g) \((3x - 1)^3 = -\frac{1}{27}\)
h) \(\left| \frac{1}{2} x - \frac{3}{4} \right| - 2 = -\frac{3}{2}\)
i) \(3 \left( \left| x - \frac{4}{5} \right| + 0.2 \right) = 0,5\)
j) \((2x + 1) \left( x - \frac{1}{7} \right) = 0\)
k) \(\left( \frac{15}{4} - 5x \right) \cdot (9x^2 - 4) = 0\)
l) \(10\sqrt{x} - 5 = 25 \text{ với } x \ge 0\)
m) \(\sqrt{x - 2} + \frac{1}{3} = 1 \text{ với } x \ge 2\)
n) \(7 \cdot 2^x + 72 \cdot 2^{x + 3} = 344\)
o) \(\frac{2}{x + 3} - \frac{1}{3} = -\frac{5}{12}\)
p) \(x - 4 = \frac{2}{3x}\)
q) \(3 = \frac{12}{x}\)
r) \(\frac{2^{x - 1}}{-3} = \frac{27}{1 - 2x} \text{ với } x \neq \frac{1}{2}\)