Tính hợp lý
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Bài 10. Tính hợp lý
a) \( A = \frac{1}{2} + \frac{1}{6} + \frac{1}{12} + \frac{1}{20} + \frac{1}{30} \)
b) \( B = \frac{2}{1.3} + \frac{2}{3.5} + \frac{2}{5.7} + \ldots + \frac{2}{2023.2025} \)
c) \( C = \frac{1}{3.5} + \frac{1}{5.7} + \frac{1}{7.9} + \ldots + \frac{1}{101.103} + \frac{1}{103.105} \)
d) \( D = \left( 1 - \frac{3}{5} \right) \left( 1 - \frac{3}{8} \right) \left( 1 - \frac{3}{11} \right) \ldots \left( 1 - \frac{3}{62} \right) \)
Bài 10. Tính hợp lý
a) \( A = \frac{1}{2} + \frac{1}{6} + \frac{1}{12} + \frac{1}{20} + \frac{1}{30} \)
b) \( B = \frac{2}{1.3} + \frac{2}{3.5} + \frac{2}{5.7} + \ldots + \frac{2}{2023.2025} \)
c) \( C = \frac{1}{3.5} + \frac{1}{5.7} + \frac{1}{7.9} + \ldots + \frac{1}{101.103} + \frac{1}{103.105} \)
d) \( D = \left( 1 - \frac{3}{5} \right) \left( 1 - \frac{3}{8} \right) \left( 1 - \frac{3}{11} \right) \ldots \left( 1 - \frac{3}{62} \right) \)