Cho hàm số \( g(x) = \frac{\sqrt{x^2 + 3x}}{2024x + 1} \). Tìm \( \lim_{x \to \infty} [g(x) - 1] \). A. \(- \frac{2025}{2024}\) B. \(- \frac{2023}{2024}\) C. \(\frac{2025}{2024}\) D. \(\frac{2023}{2024}\)