Tìm x, (10x + 3)/12 = 1 +( 6 + 8x)/9

$$\begin{gathered} 1.\frac{10\mathrm{x}+3}{12}=1+\frac{6+8x}{9} \\ 2.2(x+\frac{3}{5})=5-(\frac{13}{5}+x) \\ 3.4(0,5-1,5x)=-\frac{5x-6}{3} \\ 4.\frac{x+4}{5}-x+4=\frac{x}{3}-\frac{x-2}{2} \end{gathered}$$