Tìm x: (x + 4) - (3x - 2) = 5

Bài 1
a) (x+4) - (3x-2)= 5
b) 10(x-7)=8(x-4)+x
c) 19 – 5(x-1) = 4x + 6
d) 5(x-7)+3(x+2)=7(x-5)+2.-4.(-3).5.(-1)2020

Bài 2
1)(2n+ 9) ( n+1)
2)(5-n ) (n- 2)
3)(10- 3n ) (n- 1)
4)($n^2 -n-5$ ) ( n-1)
5)($2n^2+5n+5$) (n+2)
6) ($n^2-5) (n+1)$

Bài 3
$$\begin{gathered} A={(x-2)}^2+3 \\ B=x^2+{(y-3)}^2-1 \\ C={(3x-3)}^2+2.\left|y+1\right|-1 \end{gathered}$$