Tìm x, (x + 4)/5 - x + 4 = x/3 - (x - 2)2

A,    $\frac{x+4}{5}-x+4=\frac{x}{3}-\frac{x-2}{2}$

B,    $\frac{{\left(2x+1\right)}^2}{5}-\frac{{\left(x-1\right)}^2}{3}=\frac{7x^2-14x-5}{15}$

C,   $\frac{x+1}{9}+\frac{x+2}{8}=\frac{x+3}{7}+\frac{x+4}{6}$

 Giúp mik vs ạ !