Giải các phương trình sau: a) x^2 - 9 = (x - 3)(5x + 2); b) x^3 - 1 = (x - 1)(x^2 - 2x + 16)

a,x^2-9=(x-3)(5x+2)
b,x^3-1=(x-1)(x^2-2x+16)
c,4x^2(x-1)-x+1=0
d,x^3+4x^2-9x-36=0
e,(3x+5)^2=(x-1)^2
f,9(2x+1)^2=4(x-5)^2
g,x^2+2x=15
h,x^4-5x^3+4x^2=0
i,(3x+2)(x^2-1)=(9x^2-4)(x+1)
J,(x^2-4)-(x^2+2)(3-2x)=0
k,(3x-1)(x^+2)=(3x+1)(7x-10)
l,(2x^2+1)(4x-3)=(x-12)(2x^2+1)