Tìm x

$$\begin{gathered} a, x+\frac{3}{5}=\frac{4}{5} \\ b,\frac{2}{3}x-\frac{1}{2}=\frac{1}{10} \\ c,\frac{17}{4 }-\left|x-\frac{3}{4}\right|=\frac{-7}{4} \end{gathered}$$