Giải phương trình lượng giác: 2sin2x = 1

a,2sin2x=1,0<x<π/2
b,2sin(3x-10° )=√3, -150°<x<90°
c, 2cos2x=1,-π<x<π
d, cot(3x+2)=√3,-π/2<x<π/2
e,2IsixI= √ 2
f,cos(2x+15°)=√2/2, 0°<x<180°
g,tan(x/2+π/4)=1,0<x<2x
h,2IcosxI=√3
i,Isinx+√ 3/3I=√ 3/3
j,Icosx+1/2I=1/2