Rút gọn biểu thức sau
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a) \( \frac{10 + 2\sqrt{10}}{\sqrt{5} + \sqrt{2}} + 8 = -2 \)
b) \( \frac{2\sqrt{8} - \sqrt{12}}{\sqrt{5} + 27} = -\frac{\sqrt{6}}{2} \)
c) \( \frac{2 - \sqrt{3}}{2 + \sqrt{3}} + \frac{\sqrt{2}}{2 - \sqrt{3}} = 4 \)
d) \( \frac{(3 - \sqrt{5})(3 + \sqrt{5})}{\sqrt{10} + \sqrt{2}} = 1 \)
e) \( 1 + \frac{1}{\sqrt{2} + \sqrt{2 - \sqrt{3}}} \)
f) \( \left( \sqrt{5 + 2} \right)^2 - 8\sqrt{5} \)
\( \frac{2}{\sqrt{2} - 4} \)
a) \( \frac{10 + 2\sqrt{10}}{\sqrt{5} + \sqrt{2}} + 8 = -2 \)
b) \( \frac{2\sqrt{8} - \sqrt{12}}{\sqrt{5} + 27} = -\frac{\sqrt{6}}{2} \)
c) \( \frac{2 - \sqrt{3}}{2 + \sqrt{3}} + \frac{\sqrt{2}}{2 - \sqrt{3}} = 4 \)
d) \( \frac{(3 - \sqrt{5})(3 + \sqrt{5})}{\sqrt{10} + \sqrt{2}} = 1 \)
e) \( 1 + \frac{1}{\sqrt{2} + \sqrt{2 - \sqrt{3}}} \)
f) \( \left( \sqrt{5 + 2} \right)^2 - 8\sqrt{5} \)
\( \frac{2}{\sqrt{2} - 4} \)