Tính
Giúp em bài 2 vs ạ
----- Nội dung ảnh -----
Bài 2: Tính
a) 1: \(\left(\frac{2}{3} - \frac{3}{4}\right)^2\)
b) 15: \(\left(-\frac{2}{3}\right)^2 - \frac{7}{3}\)
c) \(\left(-\frac{1}{3}\right)^2 \cdot \frac{4}{11} + \frac{7}{11} \cdot \left(-\frac{1}{3}\right)^2\)
d) \(\left(-\frac{1}{3}\right) - \left(-\frac{3}{5}\right)^{0} + \left(1 - \frac{1}{2}\right)^{2} : 2\)
e) \(\left(\frac{1}{9}\right)^{25} : \left(\frac{1}{3}\right)^{30}\)
g) \(4 \cdot \left(-\frac{1}{2}\right)^3 + \frac{1}{2} \cdot 5\)
i) \(\frac{4^5 \cdot 9^4 - 2^6 \cdot 2^{10} \cdot 3^8 + 6 \cdot 20}{2^{10} \cdot 3^8}\)
j) \(196 : \left(\frac{7}{2}\right)^2 + \frac{1}{5} \sqrt{25} - 16\)
k) \(9.6, \left(\frac{3}{4} - \frac{5}{6}\right)^2\)
l) \(\left(-\frac{6}{7} + \frac{3}{7} - (-3)\right) = \left\{ \frac{2}{5} + \frac{-7}{8} + \frac{3}{5} - \left(-\frac{3}{2}\right) \right\}\)
Dạng 2: Tìm x
Bài 1: Tìm x, biết:
a) \(\frac{2}{3} + \frac{5}{3} x = \frac{5}{7}\)
b) \(\frac{4}{5} - x = 1\)
----- Nội dung ảnh -----
Bài 2: Tính
a) 1: \(\left(\frac{2}{3} - \frac{3}{4}\right)^2\)
b) 15: \(\left(-\frac{2}{3}\right)^2 - \frac{7}{3}\)
c) \(\left(-\frac{1}{3}\right)^2 \cdot \frac{4}{11} + \frac{7}{11} \cdot \left(-\frac{1}{3}\right)^2\)
d) \(\left(-\frac{1}{3}\right) - \left(-\frac{3}{5}\right)^{0} + \left(1 - \frac{1}{2}\right)^{2} : 2\)
e) \(\left(\frac{1}{9}\right)^{25} : \left(\frac{1}{3}\right)^{30}\)
g) \(4 \cdot \left(-\frac{1}{2}\right)^3 + \frac{1}{2} \cdot 5\)
i) \(\frac{4^5 \cdot 9^4 - 2^6 \cdot 2^{10} \cdot 3^8 + 6 \cdot 20}{2^{10} \cdot 3^8}\)
j) \(196 : \left(\frac{7}{2}\right)^2 + \frac{1}{5} \sqrt{25} - 16\)
k) \(9.6, \left(\frac{3}{4} - \frac{5}{6}\right)^2\)
l) \(\left(-\frac{6}{7} + \frac{3}{7} - (-3)\right) = \left\{ \frac{2}{5} + \frac{-7}{8} + \frac{3}{5} - \left(-\frac{3}{2}\right) \right\}\)
Dạng 2: Tìm x
Bài 1: Tìm x, biết:
a) \(\frac{2}{3} + \frac{5}{3} x = \frac{5}{7}\)
b) \(\frac{4}{5} - x = 1\)