Giải phương trình sau

$$\begin{gathered} x=\frac{1}{12}+\frac{3}{4} \\ \frac{x}{15}=\frac{3}{5}-\frac{-2}{3} \\ \left|x\right|=\frac{1}{5}+\frac{3}{4} \\ A=\frac{8}{5}+\frac{-11}{4}+\frac{7}{20}+\frac{7}{5}+\frac{-9}{4} \\ B=\frac{15}{24}-\frac{6}{26}+\frac{28}{48}-\frac{30}{39}+\frac{10}{24} \end{gathered}$$