Tính

a, A= $(\frac{1}{\sqrt{\sqrt{x}}-1} -\frac{\sqrt{x}}{x-1}): \frac{1}{\sqrt{x}+1}$ D =$( \frac{2\sqrt[]{x}}{\sqrt{x}+3}+\frac{\sqrt{x}}{\sqrt{x}-3}-\frac{3x+3}{x-9}):( \frac{2\sqrt{x}-2}{\sqrt{x}-3}-1)$
b,B= $( \frac{\sqrt{x}}{\sqrt{x}+2} + \frac{2}{\sqrt{x}-2}): \frac{x+4}{\sqrt{x}+2}$ e,E= $(\frac{1}{\sqrt{x}+2}+\frac{1}{\sqrt{x-2}}): \frac{\sqrt{x}}{x-4}$

c,C= $\frac{x-1}{\sqrt{x}(\sqrt{x}-1)} : \frac{\sqrt{x}+1}{x-1}$ F= $(1+\frac{1}{\sqrt{x}})( \frac{1}{\sqrt{x}+1} +\frac{1}{\sqrt{x}-1} -\frac{2}{x-1})$

g, T = $\frac{x+6\sqrt{x}+9}{\sqrt{x+3}} - \frac{x-4 }{\sqrt{x-2}}$ H = $(\frac{1}{\sqrt{x}+4} + \frac{1}{\sqrt{x}-4}). \frac{\sqrt{x}+4}{\sqrt{x}}$