X^2y=3+2xy+x

To solve the equation x^2y = 3 + 2xy + x, we can rearrange the terms to get a quadratic equation in terms of y:

x^2y - 2xy - x - 3 = 0

Now, we can factor out y:

y(x^2 - 2x) - (x + 3) = 0

Next, we can factor out x from the first term:

y(x(x - 2)) - (x + 3) = 0

Now, we can solve for y by dividing both sides by (x(x - 2)):

y = (x + 3) / (x(x - 2))

Therefore, the solution to the equation x^2y = 3 + 2xy + x is y = (x + 3) / (x(x - 2)).