tìm x 1((x-3)(x+2)-(x-x-3)^2=0 2)(2x-2)(2x+2)-4(x^2-3x+1)=0 3)7x(x-2)=(x-2) 4)2x(x+2)-x^2-2x0
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18 Tham khảo câu trả lời từ Trợ lý ảo Lazi 1) To solve the equation 1((x-3)(x+2)-(x-x-3)^2=0, we can simplify it step by step: 1((x-3)(x+2)-(x-x-3)^2=0 (x-3)(x+2)-(x-x-3)^2=0 (x-3)(x+2)-(0-3)^2=0 (x-3)(x+2)-9=0 (x^2-x-6)-9=0 x^2-x-15=0 Now we have a quadratic equation. We can solve it by factoring or using the quadratic formula. Factoring: (x-5)(x+3)=0 Setting each factor equal to zero: x-5=0 or x+3=0 Solving for x: x=5 or x=-3 So the solutions to the equation are x=5 and x=-3. 2) To solve the equation (2x-2)(2x+2)-4(x^2-3x+1)=0, we can simplify it step by step: (2x-2)(2x+2)-4(x^2-3x+1)=0 4x^2-4-4x^2+12x-4=0 8x-8=0 Dividing both sides by 8: x-1=0 Solving for x: x=1 So the solution to the equation is x=1. 3) To solve the equation 7x(x-2)=(x-2), we can simplify it step by step: 7x(x-2)=(x-2) 7x^2-14x=x-2 7x^2-14x-x+2=0 7x^2-15x+2=0 Now we have a quadratic equation. We can solve it by factoring or using the quadratic formula. Factoring: (7x-1)(x-2)=0 Setting each factor equal to zero: 7x-1=0 or x-2=0 Solving for x: 7x=1 or x=2 Dividing both sides by 7: x=1/7 So the solutions to the equation are x=1/7 and x=2. 4) To solve the equation 2x(x+2)-x^2-2x=0, we can simplify it step by step: 2x(x+2)-x^2-2x=0 2x^2+4x-x^2-2x=0 x^2+2x=0 Now we have a quadratic equation. We can solve it by factoring or using the quadratic formula. Factoring: x(x+2)=0 Setting each factor equal to zero: x=0 or x+2=0 Solving for x: x=0 or x=-2 So the solutions to the equation are x=0 and x=-2.