It looks like you have two equations that you want to solve or simplify. However, the way you've written them is a bit unclear.

Let's rewrite and solve the equations step by step, assuming you want to solve each equation individually.

1. For the first equation:
\[
2x - \frac{1}{27} = \frac{3}{2}x - 12
\]

2. For the second equation:
\[
-\frac{1}{27} = \frac{3}{2}x - 1
\]

### Solving the first equation:
\[
2x - \frac{1}{27} = \frac{3}{2}x - 12
\]

First, let's eliminate the fractions by multiplying the entire equation by 54 (the least common multiple of 27 and 2):
\[
54(2x) - 54\left(\frac{1}{27}\right) = 54\left(\frac{3}{2}x\right) - 54(12)
\]
This simplifies to:
\[
108x - 2 = 81x - 648
\]

Next, we solve for \(x\):
\[
108x - 81x = -648 + 2
\]
\[
27x = -646
\]
\[
x = -\frac{646}{27}
\]

### Solving the second equation:
Now, let's solve the second equation:
\[
-\frac{1}{27} = \frac{3}{2}x - 1
\]

Again, we'll eliminate the fraction by multiplying through by 54:
\[
54\left(-\frac{1}{27}\right) = 54\left(\frac{3}{2}x\right) - 54(1)
\]
Which gives us:
\[
-2 = 81x - 54
\]

Now, isolate \(x\):
\[
81x = -2 + 54
\]
\[
81x = 52
\]
\[
x = \frac{52}{81}
\]

### Summary
The solutions are:
1. For the first equation: \( x = -\frac{646}{27} \)
2. For the second equation: \( x = \frac{52}{81} \)

If you meant to combine the equations or to represent them differently, please let me know!