To solve the expression \(-\frac{10}{11} \times \frac{8}{9} + \frac{7}{18} - \frac{10}{11} \times \frac{8}{9} + \frac{7}{18}\), let's break it down step-by-step.

The expression has repetitive terms; notice that \(-\frac{10}{11} \times \frac{8}{9}\) occurs twice and \(\frac{7}{18}\) occurs twice. Let's calculate them separately:

1. Calculate \(-\frac{10}{11} \times \frac{8}{9}\):
\[
-\frac{10}{11} \times \frac{8}{9} = -\frac{10 \times 8}{11 \times 9} = -\frac{80}{99}
\]

2. Since it occurs twice, we have:
\[
-\frac{80}{99} - \frac{80}{99} = -\frac{160}{99}
\]

3. Calculate \(\frac{7}{18} + \frac{7}{18}\):
\[
\frac{7}{18} + \frac{7}{18} = \frac{14}{18} = \frac{7}{9} \quad \text{(by simplifying)}
\]

Now, combine the results:
\[
-\frac{160}{99} + \frac{7}{9}
\]

To add these, find a common denominator. The least common multiple of 99 and 9 is 99.

4. Convert \(\frac{7}{9}\) to have a denominator of 99:
\[
\frac{7}{9} = \frac{7 \times 11}{9 \times 11} = \frac{77}{99}
\]

5. Add the fractions:
\[
-\frac{160}{99} + \frac{77}{99} = \frac{-160 + 77}{99} = \frac{-83}{99}
\]

6. Simplify \(-\frac{83}{99}\). Since 83 is a prime number and doesn't divide 99 evenly, this fraction is already in its simplest form.

Thus, the result of the expression is \(-\frac{83}{99}\).