Tính :

The image shows two systems of linear equations that you need to solve:

**c)**
1. \( x + my = 2m - 1 \)
2. \(-x + y = -m + 2 \)

**d)**
1. \(-mx + y = 3m + 2\)
2. \(4x - my = 2m\)

To solve each system, use the substitution method or elimination method.

### c) Solution

Add both equations:

\[
x + my - x + y = 2m - 1 - m + 2
\]

Simplify:

\[
my + y = m + 1
\]

Factor out \(y\):

\[
y(m + 1) = m + 1
\]

If \(m \neq -1\), divide both sides by \(m + 1\):

\[
y = 1
\]

Substitute \(y = 1\) into the first equation:

\[
x + m(1) = 2m - 1
\]

Simplify:

\[
x + m = 2m - 1 \quad \Rightarrow \quad x = m - 1
\]

Thus, if \(m \neq -1\), the solution is \(x = m - 1\), \(y = 1\).

### d) Solution

Multiply the first equation by 4:

\[
-4mx + 4y = 12m + 8
\]

Subtract the second equation:

\[
-4mx + 4y - (4x - my) = 12m + 8 - 2m
\]

Simplify:

\[
-4mx + 4y - 4x + my = 10m + 8
\]

Rearrange terms:

\[
(-4m - 4)x + (4 + m)y = 10m + 8
\]

Simplifying this expression further requires knowing the specific values or conditions. Work through similar steps to find any specific numeric or conditional solutions.

For \(m = -1\) or other specific conditions, equations may not hold, or there may be no unique solution.