nAgCl=0.7175=143.5=0.005mol
nHCl(1)=1.344/22.4=0.06mol
H2 + Cl2 - -> 2HCl (1)
1l-------0.672l--->1.344l
HCl+AgNO3-->AgCl+HNO3 (2)
0.005<-----------0.005mol
mHCl(2)=0.005.36.5=0.1825g
Trong (19.27+a)g dd HCl có ag HCl
Trong 5g dd HCl có 0.1825g
< = >0.1825.(19.27+a)=5a
< = > 3.516775+0.1825a=5a
< = > 3.516775=4.8175a
< = > a=1.37
=>nHCl=0.0375
Hidro+Clo khi H=100 thì tạo ra 0.06mol HCl
mà theo PT (2) thì nHCl=0.0375mol
=>H=0.0375.100/0.06=62.5%