Cho hàm số \[f\left( x \right) = {\left( {ax + b} \right)^5}\] (với a,b là tham số). Tính \[{f^{\left( {10} \right)}}\] (1)

\[\begin{array}{*{20}{l}}{f'\left( x \right) = 5a{{\left( {ax + b} \right)}^4}}\\{f''\left( x \right) = 20{a^2}{{\left( {ax + b} \right)}^3}}\\{f'''\left( x \right) = 60{a^3}{{\left( {ax + b} \right)}^2}}\\{{f^{\left( 4 \right)}}\left( x \right) = 120{a^4}\left( {ax + b} \right)}\\{{f^{\left( 5 \right)}}\left( x \right) = 120{a^5}}\\{{f^{\left( 6 \right)}}\left( x \right) = 0}\\{ \Rightarrow {f^{\left( {10} \right)}}\left( x \right) = 0\,\,\forall x \in R \Rightarrow {f^{\left( {10} \right)}}\left( 1 \right) = 0}\end{array}\]

Đáp án cần chọn là: A