Tập nghiệm của bất phương trình \[({2^{{x^2} - 4}} - 1).\ln {x^2} < 0\]là:

Điều kiện:\[x \ne 0\]

\[({2^{{x^2} - 4}} - 1)ln{x^2} < 0 \Rightarrow \left[ {\begin{array}{*{20}{c}}{\left\{ {\begin{array}{*{20}{c}}{({2^{{x^2} - 4}} - 1) > 0}\\{ln{x^2} < 0}\end{array}} \right.}\\{\left\{ {\begin{array}{*{20}{c}}{({2^{{x^2} - 4}} - 1) < 0}\\{ln{x^2} > 0}\end{array}} \right.}\end{array}} \right.\]

\(\begin{array}{l} \Leftrightarrow \left[ {\begin{array}{*{20}{c}}{\left\{ {\begin{array}{*{20}{c}}{{2^{{x^2} - 4}} > 1}\\{{x^2} < 1}\end{array}} \right.}\\{\left\{ {\begin{array}{*{20}{c}}{{2^{{x^2} - 4}} < 1}\\{{x^2} > 1}\end{array}} \right.}\end{array}} \right. \Leftrightarrow \left[ {\begin{array}{*{20}{c}}{\left\{ {\begin{array}{*{20}{c}}{{x^2} - 4 > 0}\\{{x^2} < 1}\end{array}} \right.}\\{\left\{ {\begin{array}{*{20}{c}}{{x^2} - 4 < 0}\\{{x^2} > 1}\end{array}} \right.}\end{array}} \right.\\ \Leftrightarrow \left[ {\begin{array}{*{20}{c}}{\left\{ {\begin{array}{*{20}{c}}{x > 2;x < - 2}\\{ - 1 < x < 1}\end{array}} \right.}\\{\left\{ {\begin{array}{*{20}{c}}{ - 2 < x < 2}\\{x > 1;x < - 1}\end{array}} \right.}\end{array}} \right. \Leftrightarrow \left[ {\begin{array}{*{20}{c}}{ - 2 < x < - 1}\\{1 < x < 2}\end{array} \Rightarrow x \in ( - 2; - 1) \cup (1;2)} \right.\end{array}\)

Đáp án cần chọn là: B