Trắc nghiệm:  X + NaOH → Y + CH4O ;  Y + HCl dư → Z + NaCl, X + NaOH → Y + CH4O ;  Y + HCl dư → Z + NaCl,X + NaOH → Y + CH4O; Y + HCl (dư) → Z + NaCl,X + NaOH → Y + CH4O; Y + HCl (dư) → Z + NaCl,X + NaOH→Y + CH4O                                                 Y + HCl (dư)→Z + NaCl